๐ Example Concept & Problem
Topic: Laws of Motion
Problem:
A body of mass 2 kg is moving with a velocity of 5 m/s.
It is brought to rest by applying a constant force in 4 seconds.
Find the force applied.
๐ง Prompt to ChatGPT:
โBreak this Class 9 physics problem into simpler parts for a struggling student. Include step-by-step explanation, guiding questions, and definitions of terms like momentum and force. Keep it simple but accurate.โ
๐ ChatGPT Sample Output:
๐ Scaffolded Problem Solving โ Step by Step
๐น Step 1: Understand Whatโs Given
Letโs write down the known values:
- Mass (m) = 2 kg
- Initial velocity (u) = 5 m/s
- Final velocity (v) = 0 m/s (brought to rest)
- Time (t) = 4 seconds
- Force (F) = ?
๐ Guiding Question:
Can you identify which values are given directly in the problem?
๐น Step 2: Recall the Formula
We use Newtonโs Second Law of Motion:
F = ma
But we don’t know acceleration yet. So, we find acceleration using this formula:
a = (v – u) / t
๐ง Mini Explanation:
Acceleration means how quickly the velocity changes.
If something slows down, the acceleration is negative.
๐ Guiding Question:
What does it mean when an objectโs velocity goes from 5 m/s to 0?
๐น Step 3: Calculate Acceleration
a = (0 – 5) / 4 = -1.25 m/sยฒ
(The negative sign means itโs slowing down.)
๐น Step 4: Use F = ma
Now plug in the values:
F = 2 ร (-1.25) = -2.5 N
(The negative sign shows the force is opposite to the motion โ itโs stopping the object.)
โ Final Answer:
Force = โ2.5 N (The force is in the opposite direction of motion)
๐ Reflection & Follow-Up
๐ข Guiding Questions for Class Discussion:
- Why is acceleration negative here?
- What would happen if the object was heavier but slowed down in the same time?
๐ก Try This Practice Problem:
A 4 kg object moving at 8 m/s is stopped in 2 seconds. What force is applied?
๐ฉโ๐ซ How This Helps Struggling Students:
- Breaks the problem into bite-sized steps
- Explains formulas before applying them
- Uses guiding questions to build critical thinking
- Reinforces physical meaning (e.g., why negative force)
